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3x^2+231=-54x
We move all terms to the left:
3x^2+231-(-54x)=0
We get rid of parentheses
3x^2+54x+231=0
a = 3; b = 54; c = +231;
Δ = b2-4ac
Δ = 542-4·3·231
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-12}{2*3}=\frac{-66}{6} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+12}{2*3}=\frac{-42}{6} =-7 $
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